A particle is projected at an angle of $30^{\circ}$ from horizontal at a speed of $60 \mathrm{~m} / \mathrm{s}$. The height traversed by the particle in the first second is $\mathrm{h}_0$ and height traversed in the last second, before it reaches the maximum height, is $h_1$. The ratio $h_0: h_1$ is _________
[Take, $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$ ]

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Aicharya · Accepted Answer

$\begin{aligned} & \mathrm{S}_1=30 	imes 1-\frac{1}{2} 	imes 10 	imes 1=25 \ & \mathrm{~S}_3=30+\left(\frac{-10}{2}ight) 	imes(2 	imes 3-1)=5 \ & \frac{\mathrm{~S}_1}{\mathrm{~S}_3}=\frac{25}{5}=5\end{aligned}$

A particle is projected at an angle of $30^{\circ}$ from horizontal at a speed of $60 \mathrm{~m} /…

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