A particle is placed at the point A of a frictionless track ABC as shown in figure. It is gently pushed towards right. The speed of the particle when it reaches the point B is: ( Take g = 10 m s - 2 .

Question

Aicharya · Accepted Answer

Applying conservation of mechanical energy between point A & B , we get K E A + U A = K E B + U B ⇒ 0 + m g (1)= 1 2 m v 2 + m g × 0 . 5 ⇒ v = g = 10 m s - 1

A particle is placed at the point A of a frictionless track ABC as shown in figure. It is gently pushed…

Solution