A particle is performing a uniform circular motion along a circular of radius ' $\mathrm{R}$ '. In half the…
A particle is performing a uniform circular motion along a circular of radius ' $\mathrm{R}$ '. In half the period of revolution, its displacement and distance covered are respectively
$2 R, \pi R$
$R, \pi R$
$2 \mathrm{R}, 2 \pi \mathrm{R}$
$\sqrt{2 R}, 2 \pi R$
Solution
In half the period, particle is diametrically opposite to its initial position. Hence, its displacement is $2 \mathrm{R}$. It has covered a semicircle, hence distance covered by particle is $\pi \mathrm{R}$.
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