A particle is moving such that its position coordinates x , y are 2 m , 3 m at time t = 0 , 6 m , 7 m at…

A particle is moving such that its position coordinates x, y are 2 m, 3 m at time t=0, 6 m, 7 m at time t=2 s and 13 m, 14 m at time t=5 s. The average velocity vector Vav from t=0 to t=5 s is:
  1. 1513i^+14j^
  2. 73i^+j^
  3. 2i^+j^
  4. 115i^+j^

Solution

The position vector of the particle at time t=0 is ri=2i^+3j^
The position vector of the particle at time t=5 s is rf=13i^+14j^
The displacement of the particle is s=11i^+11j^
The average velocity vector V=11i^+11j^5

Asked in: NEET 2014

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