A particle is moving in U.C.M. with speed $V$ and radius $R$. The angular acceleration of the particle is

A particle is moving in U.C.M. with speed $V$ and radius $R$. The angular acceleration of the particle is
  1. $\frac{V^2}{R}$ Perpendicular to the plane of the circle.
  2. $\frac{V^2}{R}$ along the tangent to the circle.
  3. $\frac{V^2}{R}$ along the radius towards the centre of the circle.
  4. zero.

Solution

Concept-based. During uniform circular motion, the angular velocity is fixed therefore, the angular acceleration is zero.

Asked in: MHT CET 2022 (08 Aug Shift 1)

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