A particle is moving eastwards with a velocity of $5 \mathrm{~m} / \mathrm{s}$ in 10 seconds the velocity…
- $\frac{1}{\sqrt{2}} \mathrm{~m} / \mathrm{s}^2$ towards north-east
- $\frac{1}{2} \mathrm{~m} / \mathrm{s}^2$ towards north.
- zero
- $\frac{1}{\sqrt{2}} \mathrm{~m} / \mathrm{s}^2$ towards north-west
Solution
$\overrightarrow{\mathrm{a}}=\frac{\overrightarrow{\mathrm{V}}_{\mathrm{f}}-\overrightarrow{\mathrm{V}}_{\mathrm{i}}}{\mathrm{t}}$ $=\frac{5 \hat{\mathrm{j}}-5 \hat{\mathrm{i}}}{10}=\frac{1}{2}(\hat{\mathrm{j}}-\hat{\mathrm{i}})$ $\therefore \mathrm{a}=\frac{1}{\sqrt{2}} \mathrm{~ms}^{-2}$ towards north west
Asked in: JEE Main 2005