A particle is moving along the x -axis with its coordinate with time t given by x t = 10 + 8 t - 3 t 2 .…

A particle is moving along the x -axis with its coordinate with time t given by xt=10+8t-3t2. Another particle is moving along the y -axis with its coordinate as a function of time given by yt=5-8t3. At t=1 s, the speed of the second particle as measured in the frame of the first particle is given as v. Then vin m s-1 is ___________.

Solution

v1=8-6ti^

v2=-24t2j^

v21=580

Asked in: JEE Main 2020 (08 Jan Shift 1)

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