A particle is moving along a line according to the law $S=t^3-3 t^2+4 t-2$ where $\mathrm{S}$ is measured in…

A particle is moving along a line according to the law $S=t^3-3 t^2+4 t-2$ where $\mathrm{S}$ is measured in metres and $t$ is measured in seconds. Then the velocity (in $\mathrm{mt} / \mathrm{sec}$ ) of the particle when its acceleration is zero is
  1. $2$
  2. $\frac{1}{4}$
  3. $\frac{17}{4}$
  4. $1$

Solution

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Asked in: AP EAMCET 2017 (25 Apr Shift 1)

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