A particle is moving along a horizontal circle of radius ' $r$ ' under a centripetal force $\frac{-c}{r^2}$…

A particle is moving along a horizontal circle of radius ' $r$ ' under a centripetal force $\frac{-c}{r^2}$ where ' $c$ ' is a constant. Then, the total energy of the particle is
  1. $\frac{-c}{2 r^2}$
  2. $\frac{c}{2 r}$
  3. $\frac{-c}{2 r}$
  4. $\frac{c}{2 r^2}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (25 Apr Shift 1)

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