A particle is executing simple harmonic motion with a time period of 3 s . At a position where the displacement of the particle is $60 \%$ of its amplitude, the ratio of the kinetic and potential energies of the particle is

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Aicharya · Accepted Answer

$\mathrm{T}=3 \mathrm{~s}, \mathrm{x}=0.6 \mathrm{~A}$ $	herefore \frac{\mathrm{K} \cdot \mathrm{E}}{\mathrm{P} \cdot \mathrm{E}}=\frac{\frac{1}{2} \mathrm{~m} \omega^2\left(\mathrm{~A}^2-\mathrm{x}^2ight)}{\frac{1}{2} \mathrm{~m} \omega^2 \mathrm{x}^2}=\left(\frac{\mathrm{A}}{\mathrm{x}}ight)^2-1$ $=\left(\frac{10}{6}ight)^2-1=\frac{25-9}{9}=\frac{16}{9}$

A particle is executing simple harmonic motion with a time period of 3 s . At a position where the…

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