A particle is executing SHM along a straight line. Its velocities at distances x 1 and x 2 from the mean position are V 1 and V 2 respectively. Its time period is:

Question

Aicharya · Accepted Answer

For particle undergoing SHM, V = ω A 2 - x 2 ⇒ V 2 = ω 2 A 2 - x 2 V 1 = ω A 2 - x 1 2 ⇒ V 1 2 = ω 2 A 2 - x 1 2 ...(i) V 2 = ω A 2 - x 2 2 ⇒ V 2 2 = ω 2 A 2 - x 2 2 ...(ii) V 1 2 - V 2 2 = ω 2 x 2 2 - x 1 2 ω = V 1 2 - V 2 2 x 2 2 - x 1 2 T = 2 π x 2 2 - x 1 2 V 1 2 - V 2 2

A particle is executing SHM along a straight line. Its velocities at distances x 1 and x 2 from the mean…

Solution