A particle is executing a simple harmonic motion. Its maximum acceleration is α and maximum velocity is β . Then, its time period of vibration will be:

Question

Aicharya · Accepted Answer

ω 2 A = α ω A = β ⇒ ω = α β ⇒ T = 2 π ω = 2 π β α

A particle is executing a simple harmonic motion. Its maximum acceleration is α and maximum velocity is β .…

Solution