A particle experiences a variable force F → = 4 x i ^ + 3 y 2 j ^ in a horizontal x - y plane. Assume…

A particle experiences a variable force F=4xi^+3y2j^ in a horizontal x-y plane. Assume distance in meters and force is newton. If the particle moves from point 1,2 to point 2,3 in the x-y plane, then Kinetic Energy changes by :
  1. 25 J 
  2. 50 J
  3. 12.5 J
  4. 0 J

Solution

Using Work energy theorem,

Kinetic energy KE=W=124xdx+233y2dy

=4x2212+3y3323

=2×22-2×12+32-23=6+19

=25 Joules

Asked in: JEE Main 2022 (24 Jun Shift 1)

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