A parallel plate capacitor with plates of area 1   m 2 each, are at a separation of 0.1   m . If the electric field between the plates is 100     N / C , the magnitude of charge on each plate is: ( Take     ∈ 0 = 8.85 × 10 − 12 C 2 N - m 2 )

Question

A parallel plate capacitor with plates of area 1 &#160; m 2 each, are at a separation of 0.1 &#160; m . If the electric field between the plates is 100 &#8201; &#8201; N / C , the magnitude of charge on each plate is: ( Take &#8201; &#8201; &#8712; 0 = 8.85 &#215; 10 &#8722; 12 C 2 N - m 2 )

Aicharya · Accepted Answer

E = σ ε 0 = Q A ε 0 = 100 V / m Q = 100 × A ε 0 ⇒ Q = 100 × 1 × 8.85 × 10 - 12 C = 8.85 × 10 - 10 C

A parallel plate capacitor with plates of area 1   m 2 each, are at a separation of 0.1   m . If…

Solution

A parallel plate capacitor with plates of area 1 &#160; m 2 each, are at a separation of 0.1 &#160; m . If…

Solution

A parallel plate capacitor with plates of area 1 m 2 each, are at a separation of 0.1 m . If…