A parallel plate capacitor whose capacitance C is 14   pF is charged by a battery to a potential…

A parallel plate capacitor whose capacitance C is 14 pF is charged by a battery to a potential difference V=12 V between its plates. The charging battery is now disconnected and a porcelain plate with k=7 is inserted between the plates, then the plate would oscillate back and forth between the plates with a constant mechanical energy of _______ pJ.

(Assume no friction)

Solution

Ui=12×14×12×12 pJ  U=12CV2

=1008 pJ

Uf=10087pJ=144 pJ  Cm=kC0

Mechanical energy=ΔU

=1008-144

=864 pJ

Asked in: JEE Main 2021 (17 Mar Shift 1)

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