A parallel plate capacitor of area $60 \mathrm{~cm}^2$ and separation $3 \mathrm{~mm}$ is charged initially…

A parallel plate capacitor of area $60 \mathrm{~cm}^2$ and separation $3 \mathrm{~mm}$ is charged initially to $90 \mu \mathrm{C}$. If the medium between the plate gets slightly conducting and the plate loses the charge initially at the rate of $2.5 \times 10^{-8} \mathrm{C} / \mathrm{s}$, then what is the magnetic field between the plates ?
  1. $2.5 \times 10^{-8} \mathrm{~T}$
  2. $2.0 \times 10^{-7} \mathrm{~T}$
  3. $1.63 \times 10^{-11} \mathrm{~T}$
  4. Zero

Solution

Magnetic field between the plates in this case is zero.

Asked in: JEE Main 2013 (23 Apr Online)

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