A parallel plate capacitor is of area 6   c m 2 and a separation 3   m m . The gap is filled with…

A parallel plate capacitor is of area 6 cm2 and a separation 3 mm. The gap is filled with three dielectric materials of equal thickness (see figure) with dielectric constant K1=10, K2=12 and K3=14. The dielectric constant of a material which when fully inserted in above capacitor, gives same capacitance would be:

  1. 4
  2. 36
  3. 14
  4. 12

Solution

C=∈0Ad

C1=K1∈0A3d=K1C3

C2=K2C3

C3=K3C3

C eq = K eq C= C 3 ( K 1 + K 2 + K 3 )

Keq=K1+K2+K33=363=12

Asked in: JEE Main 2019 (10 Jan Shift 1)

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