A parallel plate capacitor is formed by two plates each of area 30 π cm 2 separated by 1   mm . A…

A parallel plate capacitor is formed by two plates each of area 30πcm2 separated by 1 mm. A material of dielectric strength 3.6×107 V m-1 is filled between the plates. If the maximum charge that can be stored on the capacitor without causing any dielectric breakdown is 7×10-6 C, the value of dielectric constant of the material is :

[Use 14πεo=9×109 N m2 C-2]

  1. 1.66
  2. 1.75
  3. 2.25
  4. 2.33

Solution

The dielectric strength given is 3.6×107 V m-1.and the separation is 1 mm. Therefore, maximum potential difference that can be applied will be,

Vmax=3.6×107×d.

Now,

C=qmaxVmaxkε0Ad=7×10-73.6×107×dk=dε0×30π×10-4×7×10-73.6×107×d=2.33

Asked in: JEE Main 2022 (24 Jun Shift 1)

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