A parallel plate capacitor having a plate separation of $2 \mathrm{~mm}$ is charged by connecting it to a $300 \mathrm{~V}$ supply. The energy density is

Question

Aicharya · Accepted Answer

The energy density of parallel plate capacitor given by $U=\frac{1}{2} \varepsilon_{0} E^{2}=\frac{1}{2} \varepsilon_{0}\left(\frac{V}{d}\right)^{2}$
$=\frac{1}{2} \times 8.85 \times 10^{-12} C^{2} / N m^{2} \times\left(\frac{300 v o l t}{2 \times 10^{-3} m}\right)$
$=0.1 \mathrm{~J} / \mathrm{m}^{3}$ *

A parallel plate capacitor having a plate separation of \(2 \mathrm{~mm}\) is charged by connecting it to a…

Solution