A parallel plate capacitor filled with oil of a dielectric constant 3 between the plates has capacitance '…

A parallel plate capacitor filled with oil of a dielectric constant 3 between the plates has capacitance ' $C$ '. If the oil is removed, then the capacitance of the capacitor will be
  1. $\frac{\mathrm{C}}{\sqrt{3}}$
  2. $3 \mathrm{C}$
  3. $\sqrt{3} \mathrm{C}$
  4. $\frac{C}{3}$

Solution

$\mathrm{C}=\frac{\mathrm{K} \varepsilon_0 \mathrm{~A}}{\mathrm{~d}}=\frac{3 \varepsilon_0 \mathrm{~A}}{\mathrm{~d}}$ After removing the oil, capacitance becomes $\mathrm{C}^{\prime}=\frac{\varepsilon_0 \mathrm{~A}}{\mathrm{~d}}=\frac{\mathrm{C}}{3}$

Asked in: MHT CET 2021 (20 Sep Shift 2)

Practice more Electrostatics questions on Aicharya