A p-n junction diode is reverse biased with a voltage of $8 \mathrm{~V}$. If the resistance of the diode is…

A p-n junction diode is reverse biased with a voltage of $8 \mathrm{~V}$. If the resistance of the diode is $4 \times 10^7 \Omega$, then the reverse saturation current is
  1. $32 \mu \mathrm{A}$
  2. $2 \mu \mathrm{A}$
  3. $0.2 \mu \mathrm{A}$
  4. $0.5 \mu \mathrm{A}$

Solution

Saturation current $ \begin{aligned} & \mathrm{I}=\frac{\mathrm{v}(\text { reverse biased voltage })}{\text { diode resistance }} \\ & =\frac{8}{4 \times 10^7}=0.2 \mu \mathrm{A} \end{aligned} $

Asked in: AP EAMCET 2023 (15 May Shift 1)

Practice more Semiconductors questions on Aicharya