A number lock has 3 rings and each ring has 8 digits. Total number of different ways in which 3 rings can be…
A number lock has 3 rings and each ring has 8 digits. Total number of different ways in which 3 rings can be rotated is
\(3^8\)
\(8^3\)
\(3 \times 8\)
\({ }^8 P_3\)
Solution
Since, it is given that a lock has 3 rings and each ring has 8 digits, so each ring can be rotated in 8 ways, therefore total number of different ways in which 3 rings can be rotated is \(8 \times 8 \times 8=8^3\). Hence, option (b) is correct.