A nucleus with mass number 240 breaks into two fragments each of mass number 120 , the binding energy per…

A nucleus with mass number 240 breaks into two fragments each of mass number 120, the binding energy per nucleon of unfragmented nuclei is 7.6 MeV while that of fragments is 8.5 MeV. The total gain in the binding energy in the process is :
  1. 0.9MeV
  2. 9.4MeV
  3. 216 MeV
  4. 804 MeV

Solution

Given binding energy per nucleon of X, Y & Z are,  7.6 MeV, 8.5 MeV & 8.5 MeV respectively.

⇒B.E. =(120×8.5)+(120×8.5)-240×7.6

⇒B.E.=2040-1824=216 MeV

Asked in: NEET 2021

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