A normal woman, whose father was colour-blind is married to a normal man. The sons would be:

A normal woman, whose father was colour-blind is married to a normal man. The sons would be:
  1. 75% colour-blind
  2. $50 \%$ colour-blind
  3. all normal
  4. all colour-blind.

Solution

The genotype of normal woman with colourblind father $=\mathrm{XX}^{\mathrm{h}}$ The genotype of normal $\operatorname{man}=X Y$ $\therefore 50 \%$ of the sons would be colourblind.

Asked in: NEET 2004

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