A non-conducting ring of radius \(0.5 \mathrm{~m}\) carries a total charge of \(1.11 \times 10^{-10}…

A non-conducting ring of radius \(0.5 \mathrm{~m}\) carries a total charge of \(1.11 \times 10^{-10} \mathrm{C}\) distributed non-uniformly on its circumference producing an electric field \(\vec{E}\) everywhere in space.
The value of the line integral \(\int_{l=\infty}^{l=0}-\vec{E} \cdot \overrightarrow{d l}(l,=0\) being centre of the ring) in volt is

Solution

\(\int_{-\infty}^{0}-\vec{E} \cdot \vec{d l}=\) potential at centre of non-conducting ring
\(=\frac{1}{4 \pi \varepsilon_{0}} \times \frac{q}{r}=\frac{9 \times 10^{9} \times 1.11 \times 10^{-10}}{0.5}=2\)

Asked in: JEE Mains - Electrostatics - Chapter Test

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