A neon-dioxygen mixture contains $64 \mathrm{~g} \mathrm{O}_2$ and $160 \mathrm{~g} \mathrm{Ne}$. If the…

A neon-dioxygen mixture contains $64 \mathrm{~g} \mathrm{O}_2$ and $160 \mathrm{~g} \mathrm{Ne}$. If the total pressure is $25 \mathrm{bar}$, calculate the partial pressure of dioxygen.
  1. 5 bar
  2. 7.5 bar
  3. 10 bar
  4. 20 bar

Solution

$\begin{aligned} & \mathrm{n}_{\mathrm{O}_2}=\frac{64}{32}=2 \mathrm{~mol} ; \mathrm{n}_{\mathrm{N}_{\mathrm{e}}}=\frac{160}{20}=8 \mathrm{~mol} \\ & x_{\mathrm{O}_2}=\frac{\mathrm{n}_{\mathrm{O}_2}}{\mathrm{n}_{\text {Total }}}=\frac{2}{2+8}=\frac{2}{10}=0.2 \\ & \mathrm{P}_{\mathrm{O}_2}=x_{\mathrm{O}_2} \times \mathrm{P}_{\text {Total }}=0.2 \times 25=5 \mathrm{bar}\end{aligned}$

Asked in: MHT CET 2023 (14 May Shift 2)

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