A near UV photon of $300 \mathrm{~nm}$ is absorbed by a gas and then re-emitted as two photons. One photon…

A near UV photon of $300 \mathrm{~nm}$ is absorbed by a gas and then re-emitted as two photons. One
photon is red with wavelength $760 \mathrm{~nm}$. Hence, wavelength of the second photon is
  1. $460 \mathrm{~nm}$
  2. $1060 \mathrm{~nm}$
  3. $496 \mathrm{~nm}$
  4. $300 \mathrm{~nm}$

Solution

Energy values are additives
$\mathrm{E}=\mathrm{E}_{1}+\mathrm{E}_{2}$
$\frac{\mathrm{hc}}{\lambda}=\frac{\mathrm{hc}}{\lambda_{1}}+\frac{\mathrm{hc}}{\lambda_{2}}$
$\frac{1}{\lambda}=\frac{1}{\lambda_{1}}+\frac{1}{\lambda_{2}}$
$\lambda=300 \mathrm{~nm}, \lambda_{1}=760 \mathrm{~nm}$
$\therefore \lambda_{2}=495.6 \mathrm{~nm}$
$\approx 496 \mathrm{~nm}$ ~

Asked in: JEE-TOPICTESTS-CHEMISTRY

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