A moving coil galvanometer, having a resistance G , produces full scale deflection when a current I G flows…

1. ${\mathrm{R}}_{\mathrm{A}}{\mathrm{R}}_{\mathrm{V}}={\mathrm{G}}^2\left(\frac{{\mathrm{I}}_0-{\mathrm{I}}_{\mathrm{g}}}{{\mathrm{I}}_{\mathrm{g}}}\right)$ and $\frac{{\mathrm{R}}_{\mathrm{A}}}{{\mathrm{R}}_{\mathrm{V}}}={\left(\frac{{\mathrm{I}}_{\mathrm{g}}}{\left({\mathrm{I}}_0-{\mathrm{I}}_{\mathrm{g}}\right)}\right)}^2\mathrm{ }$
2. ${\mathrm{R}}_{\mathrm{A}}{\mathrm{R}}_{\mathrm{V}}={\mathrm{G}}^2$ and $\frac{{\mathrm{R}}_{\mathrm{A}}}{{\mathrm{R}}_{\mathrm{V}}}=\frac{{\mathrm{I}}_{\mathrm{g}}}{\left({\mathrm{I}}_0-{\mathrm{I}}_{\mathrm{g}}\right)}$
3. ${\mathrm{R}}_{\mathrm{A}}{\mathrm{R}}_{\mathrm{V}}={\mathrm{G}}^2\left(\frac{{\mathrm{I}}_{\mathrm{g}}}{{\mathrm{I}}_0-{\mathrm{I}}_{\mathrm{g}}}\right)$ and $\frac{{\mathrm{R}}_{\mathrm{A}}}{{\mathrm{R}}_{\mathrm{V}}}={\left(\frac{{\mathrm{I}}_0-{\mathrm{I}}_{\mathrm{g}}}{{\mathrm{I}}_{\mathrm{g}}}\right)}^2$
4. ${\mathrm{R}}_{\mathrm{A}}{\mathrm{R}}_{\mathrm{V}}={\mathrm{G}}^2$ and $\frac{{\mathrm{R}}_{\mathrm{A}}}{{\mathrm{R}}_{\mathrm{V}}}={\left(\frac{{\mathrm{I}}_{\mathrm{g}}}{{\mathrm{I}}_0-{\mathrm{I}}_{\mathrm{g}}}\right)}^2$

Solution

Asked in: JEE Main 2019 (12 Apr Shift 2)

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