A moving coil galvanometer has 50 turns and each turn has an area 2 × 10 - 4   m 2 . The magnetic…

A moving coil galvanometer has 50 turns and each turn has an area 2×10-4 m2 . The magnetic field produced by the magnet inside the galvanometer is 0.02 T . The torsional constant of the suspension wire is 10-4 N m rad-1 . When a current flows through the galvanometer, a full scale deflection occurs if the coil rotates by 0.2 rad . The resistance of the coil of the galvanometer is 50 Ω . This galvanometer is to be converted into an ammeter capable of measuring current in the range 0-1.0 A . For this purpose, a shunt resistance is to be added in parallel to the galvanometer. The value of this shunt resistance, in ohms, is __________.

Solution

n=50 turnsA=2×10-4 m2
B=0.02TK=10-4
Qm=0.2 radRg=50Ω
IA=0-1.0Aτ=MB=Cθ, M=NIA 
B I g NA=Cθ
0.02× I g ×50×2×10-4=10-4×0.2
Ig=0.1A
For galvanometer, resistance is to be connected to ammeter in shunt.

Ig×Rg=I-IgS
0.1×50=1-0.1S
S=509=5.55

Asked in: JEE Advanced 2018 (Paper 2)

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