A moving coil galvanometer has 150 equal divisions. Its current sensitivity is 10 divisions per milliampere…
A moving coil galvanometer has 150 equal divisions. Its current sensitivity is 10 divisions per milliampere and voltage sensitivity is 2 divisions per millivolt. In order that each division reads 1 volt, the resistance in ohms needed to be connected in series with the coil will be
$10^3$
$10^5$
99995
9995
Solution
$I_g=15 \mathrm{~mA} \quad V g=75 \mathrm{mV}$
$\mathrm{R}=\frac{\mathrm{V}}{\mathrm{I}_g}-\frac{\mathrm{V}_g}{I_g}$