A moving car possesses average velocities of $5 \mathrm{~ms}^{-1}$, $10 \mathrm{~ms}^{-1}$ and $15 \mathrm{~ms}^{-1}$ in the first, second and third seconds, respectively. What is the total distance covered by the car in these 3 secs ?

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Aicharya · Accepted Answer

distance covered $=s=v_{\mathrm{av}} \times$ time For first second: $S_{1}=5 \times 1=5 \mathrm{~m}$ For second second: $S_{2}=10 \times 1=10 \mathrm{~m}$ For third second: $S_{3}=15 \times 1=15 \mathrm{~m}$ Total distance travelled $S=S_{1}+S_{2}+S_{3}=5+10+15=30 \mathrm{~m}$

A moving car possesses average velocities of \(5 \mathrm{~ms}^{-1}\), \(10 \mathrm{~ms}^{-1}\) and \(15…

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