A moving body is covering distances which are proportional to square of the time. Then the acceleration of…

A moving body is covering distances which are proportional to square of the time. Then the acceleration of the body is
  1. decreasing.
  2. Constant but not Zero
  3. Zero
  4. Increasing

Solution

$s \propto t^{2}$ $s=k t^{2}$ $\frac{d s}{d t}=2 k t$ $\frac{d^{2} s}{d t^{2}}=2 k$

Asked in: MHT CET 2020 (16 Oct Shift 1)

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