A moving block having mass m , collides with another stationary block having mass 4 m . The lighter block comes to rest after collision. When the initial velocity of the lighter block is v , then the value of coefficient of restitution ( e ) will be

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Aicharya · Accepted Answer

By conversation of linear momentum m v = 4 m v ′ ⇒ v ′ = v 4 Coefficient of restitution ( e ) = V e l o c i t y o f s e p a r a t i o n V e l o c i t y o f a p p r o a c h = v 4 - 0 v - 0 = 1 4 = 0.25

A moving block having mass m , collides with another stationary block having mass 4 m . The lighter block…

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