A motor operating on 100 V draws a current of 1 A. If the efficiency of the motor is $91.6 \%$, then the loss of power in units of $\mathrm{cal} / \mathrm{s}$ is

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Aicharya · Accepted Answer

$\begin{aligned} & P_{	ext {input }}=V i=100 \mathrm{~W} \ & \eta=\frac{P_{	ext {out }}}{P_{	ext {input }}}=0.916\end{aligned}$ $\begin{aligned} & P_{	ext {out }}=91.6 \mathrm{~W} \ & 	ext { Loss }=100-91.6=8.4 \mathrm{~J} / \mathrm{s}=2 \mathrm{cal} / \mathrm{s}\end{aligned}$

A motor operating on 100 V draws a current of 1 A. If the efficiency of the motor is $91.6 \%$, then the…

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