A mosquito is moving with a velocity v → = 0 . 5 t 2 i ^ + 3 t j ^ + 9 k ^   m   s - 1 and…

A mosquito is moving with a velocity v→=0.5t2i^+3tj^+9k^ m s-1 and accelerating in uniform conditions. What will be the direction of mosquitoes after 2 s ?

  1. tan-123 from x-axis
  2. tan-1856 from y-axis
  3. tan-152 from y-axis
  4. tan-152 from x-axis

Solution

Given :
v→=0.5t2i^+3tj^+9k^

v→at t=2=2i^+6j^+9k^

∴ Angle made by direction of motion of mosquito will be,

cos-1211 (from x-axis) =tan-11172

cos-1611 (from y-axis) =tan-1856

cos-1911 (from z-axis) =tan-1409

Asked in: JEE Main 2021 (16 Mar Shift 2)

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