A monkey of mass $20 \mathrm{~kg}$ is holding a vertical rope. The rope will not break when a mass of $25…
A monkey of mass $20 \mathrm{~kg}$ is holding a vertical rope. The rope will not break when a mass of $25 \mathrm{~kg}$ is suspended from it but will break if the mass exceeds $25 \mathrm{~kg}$. What is the maximum acceleration with which monkey can climb up along the rope?
$5 \mathrm{~m} / \mathrm{s}^2$
$10 \mathrm{~m} / \mathrm{s}^2$
$25 \mathrm{~m} / \mathrm{s}^2$
$2.5 \mathrm{~m} / \mathrm{s}^2$
Solution
Let $T=$ tension in the rope when monkey climb up with an acceleration $a$.
Then $T-m g=m a$
$\begin{aligned}
& 25 g-20 g=20 a \\
& 5 g=20 a \\
& \Rightarrow a=\frac{5 \times 10}{20}=2.5 \mathrm{~m} / \mathrm{s}^2
\end{aligned}$