A molecule with the formula \(\mathrm{AX}_4 \mathrm{Y}\) has all it's elements from p-block. Element A is…

A molecule with the formula \(\mathrm{AX}_4 \mathrm{Y}\) has all it's elements from p-block. Element A is rarest, monoatomic, non-radioactive from its group and has the lowest ionization enthalpy value among A, X and Y. Elements X and Y have first and second highest electronegativity values respectively among all the known elements. The shape of the molecule is :
  1. Square pyramidal
  2. Octahedral
  3. Pentagonal planar
  4. Trigonal bipyramidal

Solution

Given A is rarest, monoatomic, non-radioactive p-block element and form \(\mathrm{AX}_4 \mathrm{Y}\) type of molecule.
\(\therefore\) It is concluded that it is Xe
It is given the electronegativity of A is less than X & Y
It is given the electronegativity of \(\mathrm{X} ~\&~ \mathrm{Y}\) is highest and second highest respectively among all element.
\(\therefore \mathrm{X} ~\&~ \mathrm{Y}\) are \(\mathrm{F} ~\&~ \mathrm{O}\)
\(\therefore\) Compound is consider as \(\mathrm{XeOF}_4\) with square pyramidal shape.

Asked in: JEE Main 2025 (02 Apr Shift 1)

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