A mixture of $50.0 \mathrm{~g}$ of $\mathrm{S}$ and $100.0 \mathrm{~g} \mathrm{Cl}_{2}$ reacts of form $\mathrm{S}_{2} \mathrm{Cl}_{2}$. The mass of $\mathrm{S}_{2} \mathrm{Cl}_{2}$ formed will be

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Aicharya · Accepted Answer

$n_{0}(\mathrm{~S})=\frac{50.0 \mathrm{~g}}{32 \mathrm{~g} \mathrm{~mol}^{-1}}=1.5625 \mathrm{~mol}$
$n_{0}\left(\mathrm{Cl}_{2}ight)=\frac{100.0 \mathrm{~g}}{71.0 \mathrm{~g} \mathrm{~mol}^{-1}}=1.4084 \mathrm{~mol}$
$\xi_{\max }(\mathrm{S})=\frac{n_{0}(\mathrm{~S})}{v(\mathrm{~S})}=\frac{1.5625 \mathrm{~mol}}{2}=0.7812 \mathrm{~mol}$
$\xi_{\max }\left(\mathrm{Cl}_{2}ight)=\frac{n_{0}\left(\mathrm{Cl}_{2}ight)}{v\left(\mathrm{Cl}_{2}ight)}=\frac{1.4084 \mathrm{~mol}}{1}=1.4084 \mathrm{~mol}$
S acts as limiting reagent. Hence
$\Delta n\left(\mathrm{~S}_{2} \mathrm{Cl}_{2}ight)=v\left(\mathrm{~S}_{2} \mathrm{Cl}_{2}ight) \xi_{\max }(\mathrm{S})=(1)(0.7812 \mathrm{~mol})=0.7812 \mathrm{~mol}$
$\Delta m\left(\mathrm{~S}_{2} \mathrm{Cl}_{2}ight)=\Delta n\left(\mathrm{~S}_{2} \mathrm{Cl}_{2}ight) M\left(\mathrm{~S}_{2} \mathrm{Cl}_{2}ight)=(0.7812 \mathrm{~mol})\left(135 \mathrm{~g} \mathrm{~mol}^{-1}ight)=105.5 \mathrm{~g}$ ~

A mixture of $50.0 \mathrm{~g}$ of $\mathrm{S}$ and $100.0 \mathrm{~g} \mathrm{Cl}_{2}$ reacts of form…

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