A mixture of 2 . 3 g formic acid and 4 . 5 g oxalic acid is treated with concentrate H 2 SO 4 . The evolved…

1. $2.8$
2. $3.0$
3. $1.4$
4. $4.4$

Solution

For gases $\mathrm{n}\propto \mathrm{V}$:


${\mathrm{CO}}_2$ is absorbed by $\mathrm{KOH}$. So the remaning product is only $\mathrm{CO}$. moles of $\mathrm{CO}$ formed from both reactions $=\frac{1}{20}+\frac{1}{20}=\frac{1}{10}$
Left mass of $\mathrm{CO}$ = moles$\times$molar mass
$=\frac{1}{10}\times 28$
$=2.8 \mathrm{g}$

Asked in: NEET 2018

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