A milliammeter of resistance $40 \Omega$ has a range $0-30 \mathrm{~mA}$. What will be the resistance used…
A milliammeter of resistance $40 \Omega$ has a range $0-30 \mathrm{~mA}$. What will be the resistance
used in series to convert it into voltmeter of range $0-15 \mathrm{~V}$ ?
$640 \Omega$
$920 \Omega$
$560 \Omega$
$460 \Omega$
Solution
$\begin{aligned} R &=\frac{V}{I_{g}}-G=\frac{15}{30 \times 10^{-3}}-40 \\ &=500-40=460 \Omega \end{aligned}$