A meter bridge setup is shown in the figure. It is used to determine an unknown resistance $R$ using a given resistor of $15 Ω$ . The galvanometer $(G)$ shows null defection when tapping key is at $43 cm$ mark from end $A$ . If the end correction for end $A$ is $2 cm$ , then the determined value of $R$ will be $Ω$ .

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Aicharya · Accepted Answer

Using the conditions of a balanced wheatstone bridge and adding the end correction. 15 R = l + e L + e - l + e &#8658; 15 43 + 2 = R 102 - 45 &#8658; R = 57 45 &#215; 15 &#8658; R = 19 &#160; &#937;

A meter bridge setup is shown in the figure. It is used to determine an unknown resistance R using a given…

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