A metallic solid undergoes Frenkel defect. Its original mass, volume and density are \(M_0, V_0\) and…
A metallic solid undergoes Frenkel defect. Its original mass, volume and density are \(M_0, V_0\) and \(D_0\) respectively. After Frenkel defect the mass, volume and density are \(M, V\) and \(D\) respectively. The variations of \(M, V\) and \(D\) after Frenkel defect are
\(M=M_0, V=V_0, D=D_0\)
\(M < M_0, V < V_0, D < D_0\)
\(M>M_0, V=V_0, D>D_0\)
\(M=M_0, V < V_0, D>D_0\)
Solution
In Frenkel defect, atoms remain within the solid crystal. Only one vacancy is created. Density remains the same. Thus, \(M=M_0, V=V_0\) and \(D=D_0\). Hence, the correct option is (a).