A metallic conductor of length 1   m rotates in a vertical plane parallel to east-west direction about…

Given here,  $B_H=0.2\times {10}^{-4} \mathrm{T}$, $\omega =5 \mathrm{rad} {\mathrm{s}}^{-1}$ and $l= 1 \mathrm{m}$.

Emf induced in a rotating conducting rod is given by,

$\epsilon =\frac{1}{2}B\omega l^2$

Substituting the given values, we obtain

$\epsilon =\frac{1}{2}\times 0.2\times {10}^{-4}\times 5\times {\left(1\right)}^2=0.5\times {10}^{-4} \mathrm{V}=50 \mathrm{\mu V}$