A metal (X) of atomic weight $\mathrm{M} \mathrm{g} \mathrm{mol}^{-1}$ crystallizes in bcc lattice. Its…
- $a=\frac{2 M}{N d}$
- $a=\left(\frac{2 M}{N d}\right)^{\frac{1}{2}}$
- $\mathrm{a}=\left(\frac{2 \mathrm{M}}{\mathrm{Nd}}\right)^{\frac{1}{3}}$
- $\mathrm{a}=\left(\frac{4 \mathrm{M}}{\mathrm{Nd}}\right)^{\frac{1}{3}}$
Solution
Asked in: AP EAMCET 2017 (25 Apr Shift 1)