A metal wire has mass ( 0 . 4 ± 0 . 002 ) g , radius ( 0 . 3 ± 0 . 001 ) mm and length ( 5 ± 0 . 02 ) cm . The maximum possible percentage error in the measurement of density will nearly be:

Question

Aicharya · Accepted Answer

Density = mass volume ⇒ ρ = m π r 2 l Therefore, percentage error can be written as ⇒ d ρ ρ × 100 = d m m + 2 d r r + d l l × 100 = 0 . 002 0 . 4 + 2 0 . 001 0 . 3 + 0 . 02 5 × 100 ≈ 1 . 6 %

A metal wire has mass ( 0 . 4 ± 0 . 002 ) g , radius ( 0 . 3 ± 0 . 001 ) mm and length ( 5 ± 0 . 02 ) cm .…

Solution