A metal tape is calibrated at 25 ° C . On a cold day when the temperature is - 15 ° C , the percentage error in the measurement of length is (Coefficient of linear expansion of metal = 1 × 10 - 5 C - 1 ∘ )

Question

A metal tape is calibrated at 25 &#176; C . On a cold day when the temperature is - 15 &#176; C , the percentage error in the measurement of length is (Coefficient of linear expansion of metal = 1 &#215; 10 - 5 C - 1 &#8728; )

Aicharya · Accepted Answer

Length of the steel tape can be written as, $L = L_{0} [1 + α (T - 25 °)]$
Now, percentage error in measurement can be written as,
$|\frac{∆ L}{L} \times 100 %| = |α (T - 25 °) \times 100| = |1 \times 10^{- 5} (- 15 ° - 25 °) \times 100| = 0.04 %$

A metal tape is calibrated at 25 ° C . On a cold day when the temperature is - 15 ° C , the…

Solution

A metal tape is calibrated at 25 &#176; C . On a cold day when the temperature is - 15 &#176; C , the…

Solution

A metal tape is calibrated at 25 ° C . On a cold day when the temperature is - 15 ° C , the…