A metal rod is subjected to cycles of magnetisation at the rate of $42 \mathrm{~Hz}$. Density of the metal…
- $5^{\circ} \mathrm{C}$
- $10^{\circ} \mathrm{C}$
- $15^{\circ} \mathrm{C}$
- $20^{\circ} \mathrm{C}$
Solution
$\begin{array}{lll}
\Delta Q=m s(\Delta \theta) \\
\Rightarrow 10^{-2} \times 42 \times 60=6 \times 10^3 \times 0.1 \times 10^{-3} \times 4.2 \times \Delta \theta \\
\Rightarrow \Delta \theta=\frac{10^{-2} \times 42 \times 60}{6 \times 10^3 \times 0.1 \times 10^{-3} \times 4.2} \\
\Rightarrow \Delta \theta=10^{\circ} \mathrm{C}
\end{array}$
Asked in: AP EAMCET 2019 (20 Apr Shift 2)
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