A metal rod having coefficient of linear expansion $2 \times 10^{-5} /{ }^{\circ} \mathrm{C}$ is 0.75 m long…

A metal rod having coefficient of linear expansion $2 \times 10^{-5} /{ }^{\circ} \mathrm{C}$ is 0.75 m long at $45^{\circ} \mathrm{C}$. When the temperature rises to $65^{\circ} \mathrm{C}$, the increase in length of the rod will be
  1. 3.0 mm
  2. 0.75 mm
  3. 0.30 mm
  4. 0.15 mm

Solution

$\begin{aligned} \alpha & =\frac{\mathrm{d} l}{l \times \mathrm{dt}} \\ \mathrm{d} l & =\alpha \times l \times \mathrm{dt} \\ & =2 \times 10^{-5} \times 0.75 \times\left(65^{\circ}-45^{\circ}\right) \\ & =0.3 \times 10^{-3} \mathrm{~m}=0.30 \mathrm{~mm}\end{aligned}$

Asked in: MHT CET 2024 (11 May Shift 2)

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