A metal conductor of length $1 \mathrm{~m}$ rotates vertically about one of its ends at angular velocity 5…

A metal conductor of length $1 \mathrm{~m}$ rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earth's magnetic field is $0.3 \times 10^{-4} \mathrm{~T}$, then the e.m.f. developed between the two ends of the conductor is
  1. depends on the nature of the metal used
  2. depends on the intensity of the radiation
  3. depends both on the intensity of the radiation and the metal used
  4. is the same for all metals and independent of the intensity of the radiation.

Solution

emf. developed is given by $ \varepsilon_{\text {ind }}=\frac{1}{2} \mathrm{~B} \omega \mathrm{R}^2=50 \mu \mathrm{V} \text {. } $

Asked in: JEE Main 2004

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