A metal complex with a formula $\mathrm{MC} \ell_4 \cdot 3 \mathrm{NH}_3$ is involved in $\mathrm{sp}^3…

A metal complex with a formula $\mathrm{MC} \ell_4 \cdot 3 \mathrm{NH}_3$ is involved in $\mathrm{sp}^3 \mathrm{~d}^2$ hybridisation. It upon reaction with excess of $\mathrm{AgNO}_3$ solution gives ' x ' moles of AgCl. Consider ' x ' is equal to the number of lone pairs of electron present in central atom of $\mathrm{BrF}_5$. Then the number of geometrical isomers exhibited by the complex is ______.

Solution


1 lone pair hence 1 mole AgCl.
Complex is $\left[\mathrm{M}\left(\mathrm{NH}_3\right)_3 \mathrm{Cl}_3\right] \mathrm{Cl}$.
It shows 2 geometrical isomers $\left(\mathrm{Ma}_3 \mathrm{~b}_3\right.$ type) facial (fac) & meridional (Mer)

Asked in: JEE Main 2025 (04 Apr Shift 2)

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